using FontAwesome in PHP FPDF

Hi All,

I found it impossible to use FontAwesome 4.7.0 Free version, inside FPDF PHP engine.

When trying to upload the FontAwesome.4.7.full.otf into FPDF's Font File Generation, I'm getting an error:

Error: OpenType fonts based on PostScript outlines are not supported

So my solution, 

to re-build the FontAwesome font 4.7 free version (under same license!),

with mapping of regular characters to icons HEX CODES: 0x21 to 0xFF. 

So for example, 

character code 0x21 is now mapped to * (FontAwesome's asterisk)

And then, just use it inside PHP FPDF as follows:

// Import and prepare font for usage by engine:

$pdf->AddFont('FontAwesome47-P1','','FontAwesome47-P1.php');

...

// print FontAwesome's asterisk

$pdf->SetFont('FontAwesome47-P1' '', 14);

$pdf->Text($x, $y, chr(0x21));

Note:

Remember to upload the files FontAwesome47-P1.php + FontAwesome47-P1.z,
that generated on FPDF's Font File Generation to the FPDF's font folder.

Characters code MAP of new fonts exists as preview when opening the google-drive links below.

View MAP + DOWNLOAD: FontAwesome47-P1.otf (google drive)

View MAP + DOWNLOAD: FontAwesome47-P2.otf (google drive)

View MAP + DOWNLOAD: FontAwesome47-P3.otf (google drive)

View MAP + DOWNLOAD: FontAwesome47-P4.otf (google drive)

PHP+Z Files ready-to-use for PHP FPDF (with ISO-8859-1 encoding):

FontAwesome47-P1-4 (php+z files) DOWNLOAD (google drive)

Best regards!

Please write comments...

php merge dateranges code algorithm

Here is a code for merging date-ranges in array. The method gives new array, with the maximum mergining between the date-ranges, meaning if there is a date-range that already exists with-in other, it can just skip, so just if two or more dates can be combined into one big date-range - it will be made :) . 

 

-------------------------------Example #1:

  array 
  0 => 's' => '2020-01-06' 'e' => '2020-01-10'
  1 => 's' => '2020-01-07' 'e' => '2020-01-12'
  2 => 's' => '2020-01-13' 'e' => '2020-01-16'
  3 => 's' => '2020-01-22' 'e' => '2020-01-24'

RESULT:
array 
  0 => 's' => '2020-01-06' 'e' => '2020-01-16'
  1 => 's' => '2020-01-22' 'e' => '2020-01-24'

 

-------------------------------Example #2:

array (size=8)
  0 => 's' => '2020-01-01' 'e' => '2020-01-01'
  1 => 's' => '2020-01-03' 'e' => '2020-01-03'
  2 => 's' => '2020-01-09' 'e' => '2020-01-10'
  3 => 's' => '2020-01-11' 'e' => '2020-01-22'
  4 => 's' => '2020-01-14' 'e' => '2020-02-02'
  5 => 's' => '2020-02-02' 'e' => '2020-02-03'
  6 => 's' => '2020-02-04' 'e' => '2020-02-04'
  7 => 's' => '2020-02-05' 'e' => '2020-02-07'

RESULT:
array (size=3)           
  0 => 's' => '2020-01-01' 'e' => '2020-01-01'
  1 => 's' => '2020-01-03' 'e' => '2020-01-03'
  2 => 's' => '2020-01-09' 'e' => '2020-02-07'

 

 

And here is the CODE:

$arrDateranges = array(
    array('s' => '2020-01-22', 'e' => '2020-01-24'),
    array('s' => '2020-01-06', 'e' => '2020-01-10'),
    array('s' => '2020-01-07', 'e' => '2020-01-12'),
    array('s' => '2020-01-13', 'e' => '2020-01-16'),
);
$arrMerged = mergeDateRanges($arrDateranges);
var_dump($arrDateranges);
var_dump($arrMerged);

//---------------------------------------------------------

// helper funciton to get NEXT date (or any modified date)
function getRelativeDate($p_sDate, $p_sModify, $p_sFormatIn = 'Y-m-d', $p_sFormatOut = 'Y-m-d') {
    $oDT = DateTime::createFromFormat($p_sFormatIn, $p_sDate);
    $oDT->modify($p_sModify);
    return $oDT->format($p_sFormatOut);
}

function mergeDateRanges($p_arrDateranges) {
    // sort by start date
    usort($p_arrDateranges, function($a1, $a2) {
        return $a1['s'] === $a2['s'] ? 0 : ($a1['s'] < $a2['s'] ? -1 : 1);
    });
    
    $arrMerged = array();
    $arrLastDR = null;
    foreach ($p_arrDateranges as $arrDR) {
        if ($arrLastDR === null) {
            $arrLastDR = $arrDR;
            continue;
        }
        //
        // NOTE: dateS is sorted thus $sDateS >= $arrLastDR['s']
        //
        if ($arrDR['e'] <= $arrLastDR['e']) {
            continue; // already in the range.
        }
        // --- [e] > lastDR[e] ---
        $sLastDateE_1 = getRelativeDate($arrLastDR['e'], '+1 day');
        if ($arrDR['s'] <= $sLastDateE_1) { // lapping date-range until day+1
            $arrLastDR['e'] = $arrDR['e'];
            continue;
        }

        // there is gap, so need to create new date-range
        array_push($arrMerged, $arrLastDR);
        $arrLastDR = $arrDR;
    }

    if ($arrLastDR === null) {
        array_push($arrMerged, $arrLastDR);
    }
    return $arrMerged;
}

How to install php imap extension on Centos (or any)

The php package (extension) for IMAP is usually:

php-imap

Sometimes, for example on amazon ec2, when installing PHP ver. 5.5 or 5.6,

In order to install this (or any other) PHP extension,

that not come with the default PHP,

You should installed the one related to your PHP version.

For example,

one of my servers have PHP 5.6 installed on it,

but when running 

 yum install php-imap 

which gives:

Error: php56-imap conflicts with php-imap-5.3.29-1.8.amzn1.x86_64
Error: php56-common conflicts with php-common-5.3.29-1.8.amzn1.x86_64
Error: php55-common conflicts with php-common-5.3.29-1.8.amzn1.x86_64
 You could try using --skip-broken to work around the problem
 You could try running: rpm -Va --nofiles --nodigest 

so instead, check first which version currently installed:

yum list installed | grep php

 which gives:

php56.x86_64                          5.6.14-1.119.amzn1           @amzn-updates
php56-cli.x86_64                      5.6.14-1.119.amzn1           @amzn-updates
php56-common.x86_64                   5.6.14-1.119.amzn1           @amzn-updates
php56-imap.x86_64                     5.6.14-1.119.amzn1           @amzn-updates
php56-jsonc.x86_64                    1.3.6-1.19.amzn1             @amzn-main
php56-mbstring.x86_64                 5.6.14-1.119.amzn1           @amzn-updates
php56-mysqlnd.x86_64                  5.6.14-1.119.amzn1           @amzn-updates
php56-pdo.x86_64                      5.6.14-1.119.amzn1           @amzn-updates
php56-process.x86_64                  5.6.14-1.119.amzn1           @amzn-updates
php56-xml.x86_64                      5.6.14-1.119.amzn1           @amzn-updates 

 

Which means that your PHP version is 5.6 (you can also run php -v)

php -v

 which gives:

PHP 5.6.14 (cli) (built: Oct 16 2015 22:58:32)
Copyright (c) 1997-2015 The PHP Group
Zend Engine v2.6.0, Copyright (c) 1998-2015 Zend Technologies

All needed now is to install the correct version.

If you install php55-imap (or any other package) it won't work!

Some have several PHP versions installed.

command:

 

yum install php56-imap

 

don't forget to restart your apache after that.

service httpd restart

and done... :)

Hope it helps.

PHP | XML to Html Table elment convertion

In this thread,
I will show generic & universal function that
gets XML string,
convert it,
and display it as an HTML table.
(you can add any css style to design your table later on of course)


The following code is using XML example from http://www.w3schools.com/xml/simple.xml.
The XML looks like that:

<breakfast_menu>
  <food>
    <name>Belgian Waffles</name>
    <price>$5.95</price>
    <description>Two of our famous...</description>
    <calories>650</calories>
  </food>
  <food>
    <name>Strawberry Belgian Waffles</name>
    <price>$7.95</price>
    <description>Light Belgian waffles...</description>
    <calories>900</calories>
  </food>
  <food>
    <name>Berry-Berry Belgian Waffles</name>
    <price>$8.95</price>
    <description>Light Belgian....</description>
    <calories>900</calories>
  </food>
  <food>
    <name>French Toast</name>
    <price>$4.50</price>
    <description>Thick slices made....</description>
    <calories>600</calories>
  </food>
  <food>
    <name>Homestyle Breakfast</name>
    <price>$6.95</price>
    <description>Two eggs, bacon...</description>
    <calories>950</calories>
  </food>
</breakfast_menu>

The function xmlToHtmlTable 

gets a SimpleXMLElement parameter which points to main parent for which will print all his children,
and returns html table representing the XML as string.

The Code:

 <?php  
   
 // get XML remotely / locally / or / just set it as string '<root>...</root>'  
 $sXml = file_get_contents('http://www.w3schools.com/xml/simple.xml');  
   
 // parse XML  
 $oXML = simplexml_load_string($sXml);  
 if (!$oXML) {  
      die('xml format not valid or simplexml module missing.');  
 }  
   
 // assuming running the root  
 $oXmlRoot = $oXML; // or can be [$oXML->food]  
   
 //echo '<pre>'; print_r( $oXmlRoot ); echo '</pre>';  
 echo xmlToHtmlTable($oXmlRoot);  
   
   
 function xmlToHtmlTable($p_oXmlRoot) {  
      $bIsHeaderProceessed = false;  
        
      $sTHead = '';  
      $sTBody = '';       
      foreach ($p_oXmlRoot as $oNode) {  
           $sTBody .= '<tr>';  
           foreach ($oNode as $sName => $oValue){  
                if (!$bIsHeaderProceessed) {  
                     $sTHead .= "<th>{$sName}</th>";  
                }  
                $sValue = (string)$oValue;  
                $sTBody .= "<td>{$sValue}</td>";                 
           }  
           $bIsHeaderProceessed = true;  
           $sTBody .= '</tr>';  
      }  
        
      $sHTML = "<table border=1>  
                     <thead><tr>{$sTHead}</tr></thead>  
                     <tbody>{$sTBody}</tbody>  
                </table>";  
      return $sHTML;  
 }  

This will output:

 

Hope it helps!

MDB BLOG!




 

php | destroy/delete all sessions

I recently searched for an option deleting all running/active sessions,

for changing some important logic on my server.

Important:

just restarting apache won't help!

because php handles php-sessions by itself.

now,

I wonder how to make it, without changing php code.

The solution, is to delete the PHP session files created by PHP engine.

Step #1 - find where PHP store php files

on php.ini there is configured session.save_path 

which points to the correct path.

by default, it configured to "" (empty), and it is:

• On Ubuntu or Debian machines: saved on /var/lib/php5
  
• On RHEL and CentOS systems: saved on /var/lib/php/session
• If you need to find it: print session_save_path() on your php file.    You may run from command line:  php -r 'echo session_save_path(), "\n";'

Step #2 - just delete the files

Execute the following bash script:

rm  -f   /var/lib/php/session/*

or
rm  -f   /var/lib/php5/sess*

(-f will force delete without prompting!!) 

And that's it...

Now when a user will execute web-request, 

his session will be considered empty, 

and will be re-generated (under the same session name)

Javascript html date control (validation)

Here is a sample code for an html input date control include DATE validation!
I searched a lot for such method for integration with PHP page but was little difficult.

Here is the HTML CODE:

<input id="inputDate1" name="Field1" value="21/07/2006" type="text" onblur="validateDate(this, '/')" maxlength="10">

<button onclick="setTodayDate(this.previousSibling, '/')">today</button>

Here is the JAVASCRIPT CODE:

function validateDate(p_inputObj, delim)
{
var text = p_inputObj.value;
var errorMsgs = "Following error(s) :\n";
var isDateCorrect = true;

var delim1 = text.indexOf(delim);
var delim2 = text.indexOf(delim, delim1+1);
if (delim2 <= delim1)
{
isDateCorrect = false;
errorMsgs = errorMsgs + "- Must be in format of dd/mm/yyyy like (21/09/2008)\n";
}
else
{
var day = parseInt(text.substring(0, delim1), 10);
var splitter1 = text.substring(delim1, delim1+1);
var month = parseInt(text.substring(delim1+1, delim2), 10);
var splitter2 = text.substring(delim2, delim2+1);
var year = parseInt(text.substring(delim2+1), 10);

if (isNaN(day) || isNaN(month) || isNaN(year))
{
isDateCorrect = false;
if (isNaN(day)) { errorMsgs = errorMsgs + "- Day not in correct format!\n"; }
if (isNaN(month)) { errorMsgs = errorMsgs + "- Month not in correct format!\n"; }
if (isNaN(year)) { errorMsgs = errorMsgs + "- Year not in correct format!\n"; }
}
else
{
if (day<1)
{
errorMsgs = errorMsgs + "- Day must be between grater than 0\n";
isDateCorrect = false;
}

if (month>12 || month<1)
{
isDateCorrect = false;
errorMsgs = errorMsgs + "- Month must be between 01 to 12\n";
}
else
{
if (month==1 || month==3 || month==5 || month==7 || month==8 || month==10 || month==12 )
{
if (day>31)
{
errorMsgs = errorMsgs + "- Day must be between 1 to 31\n";
isDateCorrect = false;
}
}
else if(month==2)
{
// is leap year
if (((year % 4 == 0) && (year % 100 != 0)) || (year % 400 == 0))
{
if (day>29)
{
errorMsgs = errorMsgs + "- Day must be between 1 to 29\n";
isDateCorrect = false;
}
}
else
{
if (day>28)
{
errorMsgs = errorMsgs + "- Day must be between 1 to 28\n";
isDateCorrect = false;
}
}
}
else
{
if (day>30)
{
errorMsgs = errorMsgs + "- Day must be between 1 to 30\n";
isDateCorrect = false;
}
}
}

if (year<2000)
{
isDateCorrect = false;
errorMsgs = errorMsgs + "- Year not valid. must be more than 2000!\n";
}
else if (year>9999)
{
isDateCorrect = false;
errorMsgs = errorMsgs + "- Year must be 4 digits!\n";
}
}
}

if (isDateCorrect == true)
{
var newStr = (day<10 ? '0' : '') + day + delim +
(month<10 ? '0' : '') + month + delim +
year; // +" "+hour+":"+minute+" "+AMPM;
p_inputObj.title = '';
var date = new Date();
date.setFullYear(year, month-1, day);
p_inputObj.dateVal = date;
p_inputObj.value = newStr;
p_inputObj.style.backgroundColor='#FFFFFF';
return true;
}
else
{
//alert(errorMsgs);
errorMsgs = errorMsgs.substring(0, errorMsgs.length-1);
p_inputObj.dateVal = null;
p_inputObj.title = errorMsgs;
p_inputObj.style.backgroundColor='#ffaaaa';
p_inputObj.focus();
return false;
}
}

function setTodayDate(p_inputObj, p_delim)
{
var dtNow = new Date();
var day = dtNow.getDate();
var month = dtNow.getMonth() + 1;
var year = dtNow.getFullYear();
p_inputObj.value = (day<10 ? '0' : '') + day + p_delim +
(month<10 ? '0' : '') + month + p_delim +
year;
}

Date format if dd/MM/yyyy but it can also be MM/dd/yy or yyyy!
Enjoy... :)